(x+1)^6 Binomial Expansion

2 min read Jul 03, 2024
(x+1)^6 Binomial Expansion

Binomial Expansion of (x+1)^6

Introduction

In algebra, the binomial theorem is a powerful tool for expanding expressions of the form (x+y)^n, where n is a positive integer. In this article, we will explore the binomial expansion of (x+1)^6.

Binomial Theorem

The binomial theorem states that:

$(x+y)^n = \sum_{k=0}^{n} \binom{n}{k} x^{n-k} y^k$

where n is a positive integer, and k is an integer that ranges from 0 to n. The binomial coefficient binom{n}{k} is defined as:

$\binom{n}{k} = \frac{n!}{k!(n-k)!}$

Expansion of (x+1)^6

Using the binomial theorem, we can expand (x+1)^6 as follows:

$(x+1)^6 = \sum_{k=0}^{6} \binom{6}{k} x^{6-k} 1^k$

Simplifying the expression, we get:

$(x+1)^6 = \binom{6}{0} x^6 + \binom{6}{1} x^5 + \binom{6}{2} x^4 + \binom{6}{3} x^3 + \binom{6}{4} x^2 + \binom{6}{5} x + \binom{6}{6}$

Evaluating the binomial coefficients, we get:

$(x+1)^6 = 1 x^6 + 6 x^5 + 15 x^4 + 20 x^3 + 15 x^2 + 6 x + 1$

Final Result

The binomial expansion of (x+1)^6 is:

$(x+1)^6 = x^6 + 6x^5 + 15x^4 + 20x^3 + 15x^2 + 6x + 1$

This expansion can be useful in various algebraic manipulations and applications.

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